[KC Chiefs.com] The NFL informed the Chiefs on Wednesday that DE Jared Allen has been named the AFC Defensive Player of the Week for his performance in a 28-21 win against the Washington Redskins last Sunday.
Allen registered six tackles and recorded career-highs with 3.0 sacks, two forced fumbles and two fumble recoveries.
Allen ended the Redskins first drive of the game with a sacked and stripped QB Mark Brunell then recovered the fumble. He then turned the trick again in the third quarter when he knocked the ball from Brunell and scooped up the fumble. Finally, with Kansas City holding a slim 28-21 fourth-quarter lead, Allen recorded back-to-back sacks on second and third down, effectively ending another Washington possession and helping preserve the Chiefs 28-21 win.
